Charge 2Q and –Q are placed as shown in figure. The point a…

Physics Electrostatics Potential & Capacitance Electric Field and Potential,Defference,Energy and Dipole MCQ (Single Correct)

Charge 2Q and –Q are placed as shown in figure. The point at which electric field intensity is zero will be:

Somewhere between –Q and 2Q

Somewhere on the left of –Q

Somewhere on the right of 2Q

Somewhere on the right bisector of line joining –Q and 2Q

Text Solution

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The correct answer is:

The electric field due to a point charge ‘q’ at distance ‘r’ from it is given as :

E = ; more is q, more is r for E to have same magnitude

∴ By this mathematical analogy, electric field cannot be zero in the region iii

In region ii, electric field due to both charges is added & net electric field is towards left

∴ Along ⊥ bisector line IV electric field due to both charges will be added vectorially & can ‘t be zero

∴ E.F (net) can be zero in region I only

(by mathematical analogy explained)

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